00:01
We're asked to calculate the gibbs free energy given two reactions.
00:04
Two reactions we're given are and for this reaction we're given our delta h for the reaction is 736 .6 kilojoules and my delta s is 298 .0 joules per kelvin.
00:30
My second reaction is c yields t and here my delta h is 397 .0 kilojoules and my delta s is negative 214 .0 joules per kelvin.
00:56
Okay, so first i'm going to call this equation 1 and equation 2.
01:00
Let's find for equation 1 our delta g.
01:03
And that will equal my delta s minus t, which is 298, times 298 .0 joules per kelvin.
01:21
And then we'll have to convert our joules to kilojoules.
01:26
So my delta g will equal 736 .6 minus parentheses 298 times 0 .298.
01:39
And this will be positive 647 .8 kilojoules.
01:47
And for equation number two, our delta g will equal 397 .0 kilojoules minus 298 times negative 214 .0.
02:03
Same format.
02:12
So i've got 397 minus parentheses times 0 .214.
02:18
Whoops.
02:19
Minus negative 0 .214...