Calculate the amount of heat needed to boil \( 44.9 \mathrm{~g} \) of ethanol \( \left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\right) \), beginning from a temperature of \( 71.7{ }^{\circ} \mathrm{C} \). Be sure your answer has a unit symbol and the correct number of significant digits. ? 00 AIr
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First, we need to find the heat required to raise the temperature of the ethanol from 71.7°C to its boiling point, which is 78.5°C. We can use the formula: Q = m × c × ΔT where Q is the heat required, m is the mass of the ethanol, c is the specific heat capacity Show more…
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From the data below, calculate the total heat (in $\mathrm{J}$ ) needed to convert $0.333 \mathrm{~mol}$ of gaseous ethanol at $300^{\circ} \mathrm{C}$ and 1 atm to liquid ethanol at $25.0^{\circ} \mathrm{C}$ and 1 atm: bp at 1 atm: $78.5^{\circ} \mathrm{C}$ $\Delta H_{\mathrm{vap}}^{\circ}$: $40.5 \mathrm{~kJ} / \mathrm{mol}$ $c_{\text {gas }}$: $1.43 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}$ $c_{\text {liquid }}:$: $2.45 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}$
From the data below, calculate the total heat (in $\mathrm{J} )$ needed to convert 0.333 mol of gaseous ethanol at $300^{\circ} \mathrm{C}$ and 1 atm to liquid ethanol at $25.0^{\circ} \mathrm{C}$ and 1 atm: bp at $1 \mathrm{atm} : \quad 78.5^{\circ} \mathrm{C} \quad \Delta H_{\mathrm{vap}}^{\circ} : 40.5 \mathrm{kJ} / \mathrm{mol}$ $c_{\mathrm{gas}} : \quad 1.43 \mathrm{J} / \mathrm{g} \cdot^{\circ} \mathrm{C} \quad c_{\mathrm{liquid}} : \quad 2.45 \mathrm{J} / \mathrm{g} \cdot^{\circ} \mathrm{C}$
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