00:02
Hello students, according to the given question we have to find out the mean standard deviation values.
00:08
So, from the given data from the given data summation fi that is denoted as capital n is equal to 41 the frequency and summation fi into xi values will be equal to the total is 149.
00:29
So, now we have to calculate the mean value that is denoted as x bar is equal to summation fi into xi by capital n which is equal to 149 is divided by 41 which is equal to 3 .6341 and standard deviation is equal to square root of variance value.
00:54
So, that is equal to square root of variance is 1 by capital n summation fi into xi minus x bar whole square.
01:06
So, by substituting we get the value 8 .5734 which is under the square root source which is equal to 2 .928.
01:16
So, we have the values mean and standard deviation now we have to find the x bar minus sigma and x bar plus sigma limits.
01:29
So, by substituting 3 .6341 minus 2 .928 comma 3 .6341 plus 2 .928.
01:40
So, which is equal to 0 .7061 comma 6 .5621...