00:01
Of a benzoic acid sodium hydroxide solution after the addition of some sodium hydroxide.
00:08
Okay, so let's do this.
00:10
Let's figure out our milliliters of each.
00:16
Moles of acid, which i'm going to call hbz, just for short, will equal 30, i can do this in milliliters millimoles 30 .0 milliliters times 0 .100 millimoles per milliliter will equal 3 .00 millimoles.
00:56
Our moles of our base will be 10 .0 milliliters times 0 .200 millimoles per milliliter will be 2 .00 millimoles.
01:23
And then my concentration for each one of these will be 10 plus 10 .0 plus 30 .0 milliliters equals 40 milliliters.
01:41
So my concentrations will be divided by 40 .0 milliliters i have a 40 .0 milliliters, 0 .075 molar, 0 .050 molar.
02:14
Okay, now let's do our benzoic acid plus our oh minus will produce my benzoate and water.
02:31
So my initial concentration of this was zero...