Calculate the reverberation time of the room. Show the equations used and the step-by-step solution. L = 2.5m W = 2.5m H = 3m Volume = 18.75m³ Total Surface Area = 42.5m² Absorption Coefficient = 0.05
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Calculate the total absorption area (A) of the room: A = Total Surface Area x Absorption Coefficient A = 42.5m? x 0.05 A = 2.125m? Show more…
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A sound's reverberation time $T$ is the time that it takes for the sound level to decrease by $60 \mathrm{dB}$ (decibels) after the sound has been turned off. Reverberation time varies directly as the volume $V$ of a room and inversely as the sound absorption $A$ of the room. A given sound has a reverberation time of 1.5 sec in a room with a volume of $90 \mathrm{m}^{3}$ and a sound absorption of $9.6 .$ What is the reverberation time of the same sound in a room with a volume of $84 \mathrm{m}^{3}$ and a sound absorption of $10.5 ?$
Rational Expressions, Equations, and Functions
Formulas, Applications, and Variation
Let the reverberation time be 1.5 s for an empty hall and 1.3 s when a curtain cloth of 20 m^2 is suspended at the center of the hall. If the dimensions of the hall are 10m x 8m x 6m, calculate the coefficient of absorption of the curtain cloth. What area of the empty hall wall should be covered by the similar curtain cloth so as to reduce the reverberation time to 1.1 s?
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An auditorium (live room acoustic) has the dimensions of 7m x 15m x 30m. (a) Calculate the value of the mean free path of the sound in the auditorium. (b) When steady state conditions are reached in the auditorium, the sound pressure level is 74 dB re 20 µPa. If the average absorptivity of the walls is 0.05, calculate the rate at which sound energy is being absorbed per square meter of wall. (c) If 200 people are present, each adding 0.5m² to its total absorption, calculate the new reverberation time. [where ρ₀ = 1.21 kg/m³ and c = 343 m/s]
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