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• Calculate the theoretical yield in grams of Na2S for the reaction (the expected mass of Na2S produced on the reaction of 35.00 g of sodium (Na) and 40.0 g of Sulfur (S). Show your calculations. 

          •	Calculate the theoretical yield in grams of Na2S for the reaction (the expected mass of Na2S produced on the reaction of 35.00 g of sodium (Na) and 40.0 g of Sulfur (S). Show your calculations.

Added by Matthew A.

Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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• Calculate the theoretical yield in grams of Na2S for the reaction (the expected mass of Na2S produced on the reaction of 35.00 g of sodium (Na) and 40.0 g of Sulfur (S). Show your calculations.
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Consider the reaction between Sodium Sulfide and copper (II) Sulfide: Na2S (aq) + CuSO4 (aq) → Na2SO4 (aq) + CuS (s) A chemist allows for 3.50 g of Na2S and 8.00 g of CuSO4 to react. When the reaction is finished, the chemist collects 5.00 g of Na2SO4. Determine the percent yield for the reaction.

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6. Sodium metal (Na) reacts with Sulfur (S) to produce Sodium Sulfide (Na2S) a. Write a balanced chemical equation for this reaction. (1 point) b. If 15.00 g of sodium (Na) are combined with 10.0 g of Sulfur (S). Which substance is the limiting reactant? (Show your calculations) - (2 points) Calculate the theoretical yield in grams of Na2S for the reaction (the expected mass of Na2S produced on the reaction of 15.00 g of sodium (Na) and 10.0 g of Sulfur (S). Show your calculations. - (2 points)

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Transcript

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00:01 So welcome students to this question here we have sodium sulfide and this is given as 3 .5 grams.
00:10 We also have copper sulfate given as 8 .00 grams.
00:16 So the actual yield we're given the actual for the compound we expect sodium sulfate as 5 .00 grams.
00:28 So therefore the molar mass of we know the molar masses so therefore the first step is to determine the moles of a2s.
00:36 So we take the mass 3 .50 divided by molar mass of 78 grams per mole we have 0 .0448 moles.
00:45 We go for copper sulfate also we determine the moles 8 .00 divided by 100 this is 59 .5 gram per mole so we have 0 .0501 moles...
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