Question

Design Memo: You are tasked to design a 100000 metric tons per annum production plant of PX. The formation of PX is obtained from the following polymerisation reaction and also lead to the formation of wax (by-products). Oxygen is used as an initiator to this reaction at a concentration of 50 ppm by weight 2000C$_2$H$_4$ + O$_2$ ? (C$_2$H$_4$)2000 6C$_2$H$_4$ + O$_2$ ? (C$_2$H$_4$)12 Table 1: Boiling Points of components Components Ethylene Oxygen PX Wax Table 2: Price of components Components Ethylene Oxygen PX Wax (PX) Eq. 1 (Wax) Eq. 2 Boiling Point (°C) -103.7 -183 110 130 Price (Rands) 3587 12660 5781 0 Question 1: Using the heuristics of the destination code, classify the destination of products and impurity of the process based on the boiling point at the atmospheric pressure

          Design Memo: You are tasked to design a 100000 metric tons per annum production plant of PX. The
formation of PX is obtained from the following polymerisation reaction and also lead to the formation
of wax (by-products). Oxygen is used as an initiator to this reaction at a concentration of 50 ppm by
weight
2000C$_2$H$_4$ + O$_2$ ? (C$_2$H$_4$)2000
6C$_2$H$_4$ + O$_2$ ? (C$_2$H$_4$)12
Table 1: Boiling Points of components
Components
Ethylene
Oxygen
PX
Wax
Table 2: Price of components
Components
Ethylene
Oxygen
PX
Wax
(PX)
Eq. 1
(Wax)
Eq. 2
Boiling Point (°C)
-103.7
-183
110
130
Price (Rands)
3587
12660
5781
0
Question 1: Using the heuristics of the destination code, classify the destination of products
and impurity of the process based on the boiling point at the atmospheric pressure
        
Show more…
Design Memo: You are tasked to design a 100000 metric tons per annum production plant of PX. The
formation of PX is obtained from the following polymerisation reaction and also lead to the formation
of wax (by-products). Oxygen is used as an initiator to this reaction at a concentration of 50 ppm by
weight
2000C2H4 + O2 ? (C2H4)2000
6C2H4 + O2 ? (C2H4)12
Table 1: Boiling Points of components
Components
Ethylene
Oxygen
PX
Wax
Table 2: Price of components
Components
Ethylene
Oxygen
PX
Wax
(PX)
Eq. 1
(Wax)
Eq. 2
Boiling Point (°C)
-103.7
-183
110
130
Price (Rands)
3587
12660
5781
0
Question 1: Using the heuristics of the destination code, classify the destination of products
and impurity of the process based on the boiling point at the atmospheric pressure

Added by Matthew M.

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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Design Memo: You are tasked with designing a 100,000 metric ton per annum production plant of PX. The formation of PX is obtained from the following polymerization reaction and also leads to the formation of wax (by-products). Oxygen is used as an initiator for this reaction at a concentration of 50 ppm by weight. 2000CH4 + O2 -> (CH4)2000 (PX) (Eq.1) 6CH4 + O -> (CH4)12 (Wax) (Eq.2) Table 1: Boiling Points of Components Components | Ethylene | Oxygen | PX | Wax Boiling Point (°C) | -103.7 | -183 | 110 | 130 Table 2: Price of Components Components | Ethylene | Oxygen | PX | Wax Price (Rands) | 3587 | 12660 | 5781 | 0 Question 1: Using the heuristics of the destination code, classify the destination of products and impurity of the process based on the boiling point at atmospheric pressure.
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Transcript

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00:01 Hello students, in this question we have to discuss the stoichiometry for oxidation of butane.
00:06 2 moles of butane combined with 13 moles of oxygen to produce 8 moles of carbon dioxide and 10 moles of water.
00:22 In the first case, the mass of butane has been given to us as 9 .03 grams and we have to find out the mass of water produced.
00:36 The number of moles of butane would be equal to its given mass divided by its molar weight.
00:43 The given mass is 9 .03 gram and its molar weight is 58 .12 grams per mole.
00:52 The number of moles of butane come out to be 0 .15 mole.
00:57 2 mole of butane produce 10 moles of water.
01:08 0 .15 mole of butane would produce 10 divided by 2 multiplied by 0 .15 mole of water.
01:23 This comes out to be 0 .75 mole.
01:30 The mass of water produced would be equal to its number of moles multiplied by its molar weight.
01:37 The number of moles are 0 .75 and molar weight of water is 18 grams per mole.
01:44 The mass of water formed comes out to be 13 .5 grams...
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