00:01
Hello students, in a part of the question we want to complete the anova table for that mean of burger is calculated as 1363 .929, variance is calculated as summation of xi minus x bar the whole square by n minus 1.
00:11
On substituting we will get it as 284687 .6, standard deviation is calculated as square root of variance is 533 .5612.
00:20
Similarly, we can calculate mean of chicken as 1576 .057, variance is calculated as 567817 .7, standard deviation is calculated as 753 .5367, mean of sandwich is calculated as 1426 .786, variance is calculated as 937076 .2, standard deviation is 968 .07.
00:48
Mean of pizza is calculated as 751 .4286, variance is 30307 .69 and standard deviation is 17 .4 .091.
01:06
Overall mean is calculated as x bar is equal to 2500 plus etc plus 875 .6 divided by 28 which is equal to 1279 .3.
01:20
We can calculate total sum of squares as summation of xij minus x bar the whole square.
01:27
On substituting the values we will get the value of sst as 13687546.
01:35
Treatment sum of square is calculated as summation of ni into xi bar minus x bar the whole square.
01:43
On substituting the values we will get the value of sst are as 2768212.
01:50
Now, sum of squares of total is calculated as sst minus sstr.
01:57
On substituting the values we will get the value of sse as 10919334.
02:06
Degrees of freedom of total is n minus 1 which is 27.
02:11
Degrees of freedom of treatment is k minus 1 which is 4 minus 1 which is 3.
02:16
Degrees of freedom of error is n minus k which is 24.
02:22
Mean square of treatment is calculated as sstr divided by corresponding degrees of freedom.
02:29
On substituting the values we will get it as 2768212 divided by 3 which is equal to 922737 .2.
02:40
Similarly, mean square error is calculated as ssc divided by corresponding degrees of freedom.
02:48
On substituting the values we will get the value of mean square as 454972 .3.
02:57
F statistic is calculated as f is equal to mstr divided by mst...