Consider a column extending through the depth of the...

Name: consider a column extending through the depth of the atmosphere where kinetic energy is generated at the rate of 10 wm 2 if air in the column is initially at rest what would be the average w 88734
Uploaded: 2024-01-06T06:48:38-08:00
Duration: 4 min 22 s
Channel: Nicholas Mogoi
Description: consider a column extending through the depth of the atmosphere where kinetic energy is generated at the rate of 10 wm 2 if air in the column is initially at rest what would be the average w 88734

Consider a column extending through the depth of the atmosphere where kinetic energy is generated at the rate of 10 Wm^-2. If air in the column is initially at rest, what would be the average wind speed after five days if there were no kinetic energy dissipation?

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Transcript

00:01 So we need to calculate the kinetic energy of passing through a square meter for t equals to 10 hours.

00:13 If the wind speed is velocity, we're looking at 4 meters per second.

00:18 And also we're looking at another velocity of 8 meters per second.

00:24 Air density is given.

00:28 We're looking at 1 .23 kg per cubic meter.

00:33 We need to find the power in the wind in both cases also.

00:38 So the first thing to figure out is the volume of air passing through the area in the 10 hours.

00:45 Because again, we're looking at a multiply by v multiply by t.

00:53 So for the first 4 meters per second, we're looking at 10 multiply 4 multiply 10.

01:01 So we have 36.

01:07 This is we also multiplying by 3600.

01:12 We're converting that to seconds per hour.

01:17 So we have 144 ,000 cubic meter.

01:23 And for the 8 meters per second, we're looking at 10 into 8 into 10 into 3600.

01:32 And we're looking at 288 ,000 cubic meter.

01:39 So from here, we can find the mass of the air.

01:45 You know, using the, we have the density here, right? because again, mass equals to density multiplied by the volume respectively, which means that for 4 meters per second, we're looking at mass being equal to 1 .23 multiplied by 144 ,000...

Question

Consider a column extending through the depth of the atmosphere where kinetic energy is generated at the rate of 10 Wm^-2. If air in the column is initially at rest, what would be the average wind speed after five days if there were no kinetic energy dissipation?

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