Consider a simple "bob" pendulum with a period of 1.3 s. Imagine you take this pendulum different planet; You displace it as before but now observe the period if only 0.48 s. What is the acceleration due to gravity ("g", in m/s2) on this planet?
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We know that on the original planet, the period is 1.3 s. Let's assume the length of the pendulum is 1 meter (we can use any length as long as we use the same length for both planets). Then we can solve for g: 1.3 = 2π√(1/g) 1.3/2π = √(1/g) 1/g = (1.3/2π)^2 g = Show more…
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