00:01
Membership function mu r of x y.
00:06
Okay so so we have two scenarios when a is true then b should hold and when a is not true then she she should hold and this can be expressed by a cross b a bar cross c and in terms of membership function this is x y equals maximum of minimum of mu a of x and mu b of y and minimum and minimum of x and mu b of y and minimum of x so here mu a of x is a membership degree of x in set a and mu so that's mu a and mu a bar and which is equal to 1 minus mua is a membership degree of x in the complement of a.
01:26
And mu b of y and mu c of y are the membership degrees of y in sets b and c.
01:37
So we're given some data set here.
01:54
We can do the scenario when x equals 1 and y equals 1, then mu are 1 1 equals maximum of minimum of 0, minimum of 0, minimum of 1 .4, now we can do when x equals 1 and y equals 2, then mu r of 1 2 equals maximum of minimum of 0 and 0 .4 and minimum of 1 and 0 .3, which is equal to 0 .3.
02:30
And so on, you calculate this for x -1 through 4 and y -1 -36.
02:38
So we have x and y, 1, 2, 3, 4, 5, 6, 1, 2, 3, 4, 0 .3, 0 .5, 0 .6, 0 .5, and 0 .3.
02:56
0 .4, 0 .6, 0 .4, 0 .6, 0 .4 and 0 .3, and 0 .4, 0 .3, and 0 .4, 1 .4 .0 .4.
03:07
0 .8, 0 .3, 0 .3, 0 .3, 0 .5, 0 .6, 0 .5, and 0 .3.
03:21
Okay...