consider the decomposition of 10.5 g of magnesium diboride at 1135K after 185 seconds 8.76g remains. MgB2(s) --> Mg(s)+2B(s) assume the reaction follows first-order kinetics. whats is the rate constant?
Added by Thomas T.
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The molar mass of MgB2 is calculated as follows: - Molar mass of Mg = 24.31 g/mol - Molar mass of B = 10.81 g/mol - Molar mass of MgB2 = 24.31 g/mol + 2 × 10.81 g/mol = 46.93 g/mol Now, calculate the initial moles of MgB2: \[ \text{Initial moles of Show more…
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