Consider the following. $64 + 125x^3$ Use the following factorization formulas involving cubes to factor the expression. Factorizations with Cubes Perfect cube $a^3 + 3a^2b + 3ab^2 + b^3 = (a + b)^3$ Perfect cube $a^3 - 3a^2b + 3ab^2 - b^3 = (a - b)^3$ Difference of two cubes $a^3 - b^3 = (a - b)(a^2 + ab + b^2)$ Sum of two cubes $a^3 + b^3 = (a + b)(a^2 - ab + b^2)$
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