Consider the following balanced chemical equation: 4KO2(s) + 2H2O(l) ? 4KOH(s) + 3O2(g) Determine the mass (in g) of KOH formed if 50.6 g of KO2 reacts with 50.6 g of H2O.
Added by Kathy T.
Step 1
Determine the limiting reactant: To determine the limiting reactant, we need to compare the amount of each reactant to the stoichiometric ratio in the balanced equation. Let's start with KO2: 50.6 g KO2 x (1 mol KO2/71.10 g KO2) = 0.713 mol KO2 0.713 mol KO2 x (4 Show more…
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