Question

Immediately after closing A. the switch S, current through battery is 7.5 A Immediately after closing B. the switch S, current through 2 $\Omega$ resistor will be 5 A In steady state, charge on C. capacitor will be 40 $\mu$C In steady state, current D. through 4 $\Omega$ resistor will be 10 A

          Immediately after closing
A. the switch S, current
through battery is 7.5 A
Immediately after closing
B. the switch S, current
through 2 $\Omega$ resistor will be
5 A
In steady state, charge on
C. capacitor will be 40 $\mu$C
In steady state, current
D. through 4 $\Omega$ resistor will be
10 A

Immediately after closing
A. the switch S, current
through battery is 7.5 A
Immediately after closing
B. the switch S, current
through 2 Ω resistor will be
5 A
In steady state, charge on
C. capacitor will be 40 μC
In steady state, current
D. through 4 Ω resistor will be
10 A

Added by Jeffrey C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Darshan Maheshwari

04/11/2022

Step 1

5 A. - When the switch S is closed, the capacitor starts to charge. - Initially, the capacitor is uncharged, so it acts as a short circuit. - Therefore, the current through the battery is determined by the total resistance in the circuit. - The total resistance is Show more…

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Consider the following circuit. At t = 0, the capacitor is uncharged and switch S is open. Choose the correct statement(s). 4 μF 4Ω 10 V S 2Ω Immediately after closing the switch S, the current through the battery is 7.5 A. Immediately after closing the switch S, the current through the 2Ω resistor will be 5 A. In steady state, the charge on the capacitor will be 40 C. In steady state, the current through the 4Ω resistor will be 10 A.