Question

Consider the following endothermic process at equilibrium: C(s) + COâ‚‚(g) = 2 CO(g). Describe what will happen if the following stresses are applied: (a) CO is removed from the reaction vessel. (b) C is added to the reaction vessel. (c) A catalyst is added to the reaction vessel. (d) The volume of the reaction container is decreased. (e) The temperature of the reaction mixture is increased. (f) Write the equilibrium expression.

          Consider the following endothermic process at equilibrium: C(s) + COâ‚‚(g) = 2 CO(g). Describe what will happen if the following stresses are applied: (a) CO is removed from the reaction vessel. (b) C is added to the reaction vessel. (c) A catalyst is added to the reaction vessel. (d) The volume of the reaction container is decreased. (e) The temperature of the reaction mixture is increased. (f) Write the equilibrium expression.
        
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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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Consider the following endothermic process at equilibrium: C(s) + COâ‚‚(g) = 2 CO(g). Describe what will happen if the following stresses are applied: (a) CO is removed from the reaction vessel. (b) C is added to the reaction vessel. (c) A catalyst is added to the reaction vessel. (d) The volume of the reaction container is decreased. (e) The temperature of the reaction mixture is increased. (f) Write the equilibrium expression.
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Transcript

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00:02 In this problem, we're going to consider the following exothermic equilibrium and how the changes would affect the equilibrium mixture of the gases.
00:12 A catalyst is added to the mixture.
00:15 This will not affect the equilibrium mixture, except equilibrium will be reached faster, although the concentrations will not change.
00:25 This is because a catalyst lowers the activation energy, but it does not affect the position of equilibrium.
00:30 For b, carbon dioxide is added to the system.
00:35 This will cause the equilibrium to shift left because based on the chalachalier's principle, the equilibrium will shift to offset any change to the equilibrium.
00:48 If we increase the concentration of the products, it will shift towards reactants to use the products.
00:55 So for c, we add reactant carbon monoxide.
01:00 So in this case, it will shift to the right towards the products to use up carbon monoxide.
01:07 The reaction mixture is heated.
01:09 So if we heat this reaction, the reaction will shift away from the side of the heat.
01:14 This is exothermic, so heat is on the product side...
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