Question

Consider the non-right triangle shown below that has side lengths of 1.4, 1.759 and 2.55 cm and interior angle measures of 0.72, $\alpha$, and $\beta$ rad. a. What is the value of $\alpha$? $\alpha$ = (14sin(0.72))/1.759 b. What is the value of $\beta$? $\beta$ =

          Consider the non-right triangle shown below that has side lengths of 1.4, 1.759 and 2.55 cm and interior angle measures of 0.72, $\alpha$, and $\beta$ rad.
a. What is the value of $\alpha$?
$\alpha$ = (14sin(0.72))/1.759
b. What is the value of $\beta$?
$\beta$ =

Consider the non-right triangle shown below that has side lengths of 1.4, 1.759 and 2.55 cm and interior angle measures of 0.72, α, and β rad.
a. What is the value of α?
α = (14sin(0.72))/1.759
b. What is the value of β?
β =

Added by Linda W.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert James Kiss

05/09/2023

Step 1

4 = sin(0.72)/1.759 sin(B) = (1.4 * sin(0.72))/1.759 sin(B) ≈ 0.564 B ≈ sin^(-1)(0.564) B ≈ 34.2 degrees Show more…

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Consider the non-right triangle shown below that has side lengths of 1.4, 1.759 and 2.55 cm and interior angle measures of 0.72, , and rad 1.4 cm B 1.759 cm 0.72rad 2.55 cm a.What is the value of ? 14sin(0.72)/1.759 Preview b.What is the value of = Preview