00:01
Equilibrium constant is the ratio of the equilibrium concentration of the product to that of the reactant.
00:07
In this problem, we're given with an equilibrium reaction involving iron 3 with thiosionate to form iron thiosyanate.
00:16
In this problem, specifically we are given that initially that the concentration of the reactants are 6 and 10 molar.
00:25
So that's 6 for f .a.
00:26
3 plus and 10 for s.
00:28
C and minus.
00:29
And we want to find the equilibrium constant, kc, if it is given that at equilibrium, the concentration of the product is for molar.
00:40
So let us start by establishing the expression for kc.
00:45
So as has been said, this is the ratio of the concentrations at equilibrium of the product, which is f -e -s -c -n -2 -plus, and the concentration of the reactants.
00:59
So there are two reactants, what we will do is to multiply their equilibrium concentrations as shown here.
01:06
Now in case the reaction shows coefficients for this species, so we will deal with those coefficients by raising the concentrations by the respective coefficients.
01:20
But as we can see here, the coefficients are one for each of this, and so each of this equilibrium concentration is raised by one.
01:29
Moving on, let's find the concentration or the change in the concentration.
01:37
So as the reaction proceeds, let us say that x -molar of the reactants react to form x -molar of the product.
01:47
So we have them here negative for x and negative x for both reactant because of the fact that their concentration will decrease...