00:01
We're given an unbalanced redox reaction and asked to balance it in acidic solution.
00:07
I'll use the half reaction technique.
00:10
One half reaction will be the dichromate, cr2o7, 2-, going to chromium 3+.
00:19
First we balance the chromiums by putting a 2 in front of the chromium 3+.
00:25
Then we balance the oxygens.
00:28
We have 7 oxygens and no oxygens.
00:31
We balance oxygens with waters, so we'll add 7 h2os.
00:36
This introduced 14 hydrogens, so in an acidic environment we balance hydrogens with h+.
00:44
So we'll have 14 h+.
00:46
Then we balance charges with electrons...