We have a reaction:
\[ 2 \mathrm{NH}_{3}(g) \rightarrow \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \]
with a rate law:
\[ \text{rate} = (0.208 \, \mathrm{s}^{-1})[\mathrm{NH}_{3}] \]
The initial concentration of \( \mathrm{NH}_{3} \) is \( 1.18 \, M \), and we need to
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