Convert the following binary MAC address to hexadecimal form. Please show your working; failure to do so will only gain under half marks: 11000001-01011100-00001101-00010101-11000000-01010111
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To do this, group the binary digits into sets of four, starting from the right. Then, convert each group of four binary digits to its hexadecimal equivalent. Show more…
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Convert the following binary numbers into their hexadecimal equivalents: (a) $11001111_{2}$ (b) $110011110_{2}$ (a) Grouping bits in fours from the right gives: $\underbrace{1100}_{\mathrm{C}} \underbrace{11 \|}_{\mathrm{F}}$ and assigning hexadecimal symbols to each group gives as above, from Table $10.2$. Thus, $11001111_{2}=\mathbf{C F}_{16}$ (b) Grouping bits in fours from the right gives: $\underbrace{0001}_{1} \underbrace{1001}_{9} \underbrace{1110}_{\mathbf{E}}$ and assigning hexadecimal symbols to each group gives as above, from Table $10.2$. Thus, $110011110_{2}=19 \mathbb{E}_{16}$ (d) Converting from hexadecimal to binary The above procedure is reversed; thus, for example, $$ 6 \mathrm{CF} 3_{16}=0110110011110011 $$ from Table $10.2$ i.e. $6 \mathrm{CF} 3_{16}=110110011110011_{2}$
Convert $(1100001100011)_{2}$ from its binary expansion to its hexadecimal expansion.
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