Determine if the following functions are concave, convex or neither. (d) $f(x, y) := 3x + y^2$. (c) $f(x, y) := x^{1/2}y^{1/2}$ (on $\mathbb{R}^2_{++}$). (f) $f(x, y) := x^3 - x^2 - y^2$.
Added by Derrick T.
Close
Step 1
Taking the second-order partial derivatives, we get: f_xx = 2 f_yy = 2 Since both second-order partial derivatives are positive, we can conclude that the function is convex. (c) f(x, y) = √(1/2|y|): To determine if this function is concave or convex, we need Show more…
Show all steps
Your feedback will help us improve your experience
Imogen Dell and 95 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Establish whether the following functions are concave, convex, strictly concave, strictly convex, or any: a. f(x1, x2) = x1^2 + x2^2 b. f(x1, x2) = -x1^2 - 4x2^2 c. f(x1, x2) = x1 + 3x1x2 + 6x1^2 + x2^2 d. f(x1, x2) = e^x1 + e^x2 - x1 - x2
Duncan N.
For each of the following functions, determine whether it is convex, concave, quasiconvex, or quasiconcave: (a) f(x) = e^x - 1 on R (b) f(x1,x2) = x1x2 on R^2++ (c) f(x1,x2) = 1/(x1x2) on R^2++ (d) f(x1,x2) = x1/x2 on R^2++ (e) f(x1,x2) = x1^2/x2 on R x R++ (f) f(x1,x2) = x1^alpha x2^1-alpha, where 0 <= alpha <= 1, on R^2++.
Madhur L.
Sri K.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD