Question

Decide what values of the variable cannot possibly be solutions for the equation. Do not solve.\\ $\frac{1}{x-4} + \frac{1}{x+3} = \frac{1}{x^2 - x - 12}$ \\ Select the correct choice below and, if necessary, fill in the answer box to complete your choice.\\ A. The solutions cannot include $oxed{ }$.\\(Type an integer or a fraction. Use a comma to separate answers as needed.)\\B. There are no numbers that would have to be rejected as potential solutions.

          Decide what values of the variable cannot possibly be solutions for the equation. Do not solve.\\
$\frac{1}{x-4} + \frac{1}{x+3} = \frac{1}{x^2 - x - 12}$ \\
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.\\
A. The solutions cannot include $oxed{ }$.\\(Type an integer or a fraction. Use a comma to separate answers as needed.)\\B. There are no numbers that would have to be rejected as potential solutions.

$Decide what values of the variable cannot possibly be solutions for the equation. Do not solve. (1)/(x-4) + (1)/(x+3) = (1)/(x^2 - x - 12) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The solutions cannot include oxed. (Type an integer or a fraction. Use a comma to separate answers as needed.) B. There are no numbers that would have to be rejected as potential solutions.$

Added by F-Tima H.

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