From the figure, when $x=0$, $y=b$.
Substitute these values into the equation:
$b = k(0-a)^2$
$b = k(-a)^2$
$b = ka^2$
So, $k = \frac{b}{a^2}$.
Therefore, the equation of the curve is $y = \frac{b}{a^2}(x-a)^2$.
The area A under the curve is given by the integral
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