00:01
Hello, here we have a given the sum of the series that is summation of n is equal to one up to infinite a n that is equal to limit n tends to infinite this is where we have limit n tends to infinite s of n.
00:22
So, where s n is the sum of the nth term.
00:24
Now, according to the formula hence from here we can get it as that is s n we have a given that is n square minus 1 divided by 9 n square plus 1.
00:32
So, we can get it as that is limit n tends to infinite and we have a s n that is n square minus 1 divided by 9 n square plus 1.
00:44
So, here after putting the infinite value.
00:46
So, we have a form of infinite divided by infinite.
00:49
So, from here taking n square from the numerator we can write as limit n tends to infinite n square 1 minus of 1 divided by n square and from the denominator if you take n square common.
01:03
So, we have n square multiplied by 9 plus of 1 divided by n square now here n square and n square will be cancelled out...