Determine the energy that is needed to remove a neutron from $_{3}^{7} \mathrm{Li}$ to produce $_{3}^{6}$ Li plus a free neutron. [Hint: Compare the mass of $_{3}^{7}$ Li and that of $_{3}^{6} \mathrm{Li}+^{1}_{0} \mathrm{n} ].$
Added by Stephen G.
Step 1
The mass of $_{3}^{7}$ Li is 7.016003 u, and the mass of $_{3}^{6}$ Li plus a free neutron is 6.015122 u + 1.008665 u = 7.023787 u. Therefore, the mass difference is: Δm = (7.023787 u) - (7.016003 u) = 0.007784 u Show more…
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