00:01
Solve the given question.
00:02
In this question we have to calculate the force on each two that is force on the a, b and c.
00:09
Let's make an angle here is the angle theta so here is also angle theta.
00:16
This angle is pi.
00:19
The distance is c is 8 feet.
00:23
Here the distance let's call point m is 8 feet.
00:27
So by using the pythagoras theorem we can calculate this length also.
00:32
So first of all calculate the value of tan of theta in triangle b c.
00:40
Let it call the point is d.
00:44
So tan theta equals to its 8 feet cd 8 upon 8 which gives theta equals to tan inverse 1 that is theta equals to 45 degree.
00:59
Similarly we have to calculate the tan phi.
01:02
Tan phi is equals to here the distance 8 feet and 6 feet that is 8 by 6.
01:09
On solving this we get phi equals to tan inverse 8 by 6 that is phi equals to 53 .13 degree.
01:21
That is theta is 45 degree and phi is 53 .13 degree.
01:31
Now we have to calculate the force at point b.
01:37
Fbd free body diagram of the member of stress.
01:44
So we can say here is a force b that is fbc and fba due to point a.
01:49
The forces along the both the component a and t, x axis and y axis.
01:54
Here the value of p1 equals to 800 lb and p of 2 equals to 400 lb.
02:03
Now we have at equilibrium condition at equilibrium condition summation f of x equals to 0.
02:19
So the force along the x axis is given by minus of fba cos phi.
02:29
Here is the p1 in the downward direction.
02:35
Now my ba cos phi minus of p2 that is plus f of bc cos theta is equals to 0...