00:01
As given in the question that only the x component of each force has a moment about z -axis.
00:09
For example, let's suppose this is the q and if we take the component of q in x direction, then let's say it is qx and y direction, let it be qy.
00:24
So we can see that here that qy passes through the axis of rotation.
00:36
So moment generated by qy will be equal to 0.
00:40
Similarly, the moment generated by the force p will be only this one, this force, that is, let's say this is px, which will be equals to p cost 30, and qx will be equal to p cost 30, and qx will will be equal to q cost 25 degree.
01:11
So we know that the moment of the force equals to, that is moment is equals to sum of force into, that is perpendicular force from the axis of rotation and the radius from the axis of rotation.
01:26
That is, if this is the axis of rotation, then the force which is perpendicular to this axis, that is let's say, this one acting at with 90 degree and this is the radius of rotation that is r and this is f.
01:46
Something like a door hinged at its axis of rotation and it able to turn...