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Hello students.
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Today we will discuss about this question.
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In this question, we need to find the allocation of the budget among the three media that is television, television, that is equal to question mark, radio is equal to question mark, and online that is equals to question mark.
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And then we need to find the total audience reached that is equals to question mark.
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So here, first of all, we can say that let number of tv advertisement that will be x.
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So here number of tv advertisement that will be x, number of radio ads, that is y, and online ads that will be supposed z.
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So therefore, given in the table, that is, the total audience, that will be the total audience, that will be 1110 -3 -0x plus 1 -8 -3 -0 -0 -y plus 3 -0 -0 -z.
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Now, we have to maximize the total audience.
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So therefore, the objective function, that is, maximize a is equals to 1110 -3 -0x plus 1.
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18000 y plus 30300 z.
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Now the total cost of ads, that is 1 500x plus 250y plus 500 z.
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Now the budget available, that is $2 .333 .0.
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So therefore, 1 500x plus 250y plus 500gz, that is, that is $1 ,333000.
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So therefore, is less than or equals to 2 -3 -0...