00:01
This problem wants us to divide 21x to the third z to the sixth minus 12x to the seventh z to the sixth by negative 4x to the fourth z to the third.
00:09
And when we are dividing we can think of this as a fraction and since we're dividing with a monomial, what we can do is set our terms on top to be divided by that monomial individually, and then simplify them separately and then see what our result comes to.
00:23
So that would be the 21x to the third z to the sixth over negative 4x to the fourth z to the cube, and then minus 12x to the seventh z to the sixth, and then divided by our negative 4x to the fourth z to the third.
00:39
So now we'll focus on them as simplifying fractions individually.
00:43
21 over negative 4 won't simplify, so we'll leave that as negative 21 fourths.
00:47
X to the third of x to the fourth, we'll get rid of all of our x's on top and just leave 1x on bottom.
00:52
Then we have z to the sixth over z to the third, which will get rid of all of our z's on bottom, and just leave us with 3z's on top...