Drag and drop your answers into the blanks. For the quadratic function f(x)=2(x-3)^(2)-2, the vertex is at and the equation of the axis of symmetry is
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The vertex of a quadratic function in the form f(x) = a(x-h)^(2) + k is given by the coordinates (h, k). In this case, the quadratic function is f(x) = 2(x-3)^(2) - 2. Comparing this to the general form, we can see that h = 3 and k = -2. Therefore, the vertex of Show more…
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