Question

10 kN/m 20 kN 30 kNm B G A C 2m 2m 6m y z 

          10 kN/m
20 kN
30 kNm
B
G
A
C
2m
2m
6m
y
z
10 kN/m 20 kN 30 kNm B G A C 2m 2m 6m y z

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Draw the cross-section effect diagrams (N, T, M) of the load-bearing system in the figure. 10 kN/m 20 kN 30 kNm B A C 2m 2m 6m
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Transcript

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00:02 Students from the lever diagram cantilever diagram we have to draw the shear force diagram and bending moment diagram so first we have to calculate the parameters for shear force diagram force diagram so we'll get point x equal to 0 we can get the reaction ra equal to 30 kilo newton because here the reaction ra equal to 20 kilo newton plus 40 kilo newton divided by 2 that is equal to 30 kilo newton so here at point x equal to 0 the reaction is 30 kilo newton so the next we have point a and b we can write rab that is equal to 30 minus 20 that is 10 kilo newton and in third section point b and c we can write rbc that is equal to 10 minus 40 that is minus 30 kilo newton next we can write at point c and d we can write rcd equal to minus 30 kilo newton because in this from the diagram we can say the shear force is constant after point c shear force is constant so then next we can say at point d we have rd equal to 30 kilo newton so from the calculated values we can get them shear force diagram as so from this shear force diagram we can say right at point a we have a 30 kilo newton and point b we have the two shear forces namely 20 kilo newton and minus 10 kilo newton at point c we…
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