00:01
Hello on, the question that is given over here, it says that a thin rod extends along a x axis from z equal to minus d to z equal to d.
00:09
The rod carries a charge uniformly distributed along its length with linear charge density.
00:16
We are going to integrate over the charge distribution to calculate the potential at point t1 with the coordinates 0 ,0 and 2d.
00:33
Let us consider the linear chart density of the rod to be lambda.
00:43
The length of the rod is 2d minus d2 plus b.
00:53
So the potential due to the rod will be equal to v is equal to k lambda integral of d, d plus 2d, 1 by z, dz.
01:11
So we will be equal to k lambda ln3.
01:17
Will be equal to 9 .8875 into 10 to the power of 9 lambda.
01:26
So this is the potential at d -d -2...