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Establish the identity: 3cotθ - cotθ + 2csc²θ + cotθ = cscθ 

          Establish the identity: 3cotθ - cotθ + 2csc²θ + cotθ = cscθ

Added by Lauren D.

Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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Establish the identity: 3cotθ - cotθ + 2csc²θ + cotθ = cscθ
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Transcript

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00:01 To establish this identity, okay? cosign of theta times tangent of theta plus cotangent of theta equals cossecond of theta.
00:31 Okay, so this is equivalent to, let's look at the left side of the identity, okay? so left side equals cosine of theta times sine of theta over cosine of theta plus cosine of theta over sine of theta equals okay we can distribute cosine of theta to the first fraction and to the second fraction if you distribute cosine of theta to the first fraction you have okay we can cancel the cosine of theta so we have sine of theta plus cosine of theta over of theta times cosine of theta is cosine of theta squared over sine of theta.
01:47 Okay, for the first fraction, the denominator is actually one.
01:53 So i can multiply both numerator to the first fraction by sine of theta.
01:58 So you have sine of theta squared over sign of theta plus cosine of theta squared over sine of theta...
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