00:01
Let's establish this identity.
00:03
On the left, we have tangent theta over tangent theta minus 1.
00:06
Equals 1 over 1 minus cotangent theta.
00:09
So let's consider the left side expression and that equals tangent theta over tangent theta minus 1.
00:20
Now, to make the numerator of this left side expression as 1, we should divide the numerator by tangent theta.
00:28
And if you divide the numerator by tangent theta, we should also divide its denominator by tangent theta.
00:37
So this cues, you see that tangent theta divided by tanning theta, and that is 1.
00:46
So we can write the numerator as 1 divided by, in the denominator, we have tangent theta minus 1 divided by tangent theta.
00:58
So this basically is the answer for this question.
01:04
We have written the left side as a fraction of 1 over the denominator.
01:10
The denominator expression is tangent theta minus 1 over tangent theta...