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xercise 24.27 - Enhanced - with Solution Compare the total energy stored in the capacitor system when they connected to the applied potential in series and in parallel. "You have two identical capacitors and an external potential source. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Transferring charge and energy between capacitors Submit Previous Answers Correct IDENTIFY: Use the rules for series and for parallel capacitors to express the voltage for each capacitor in terms of the applied voltage. Express $U$, $Q$, and $E$ in terms of the capacitor voltage. SET UP: Let the applied voltage be $V$. Let each capacitor have capacitance $C$. $U = \frac{1}{2}CV^2$ for a single capacitor with voltage $V$. EXECUTE: Series: The voltage across each capacitor is $V/2$. The total energy stored is $U_s = 2(\frac{1}{2}C(V/2)^2) = \frac{1}{4}CV^2$ Parallel: The voltage across each capacitor is $V$. The total energy stored is $U_p = 2(\frac{1}{2}CV^2) = CV^2 \rightarrow U_p = 4U_s$ Part B Compare the maximum amount of charge stored in the capacitor system in each case. Submit Previous Answers Request Answer Incorrect; Try Again; 4 attempts remaining

          xercise 24.27 - Enhanced - with Solution
Compare the total energy stored in the capacitor system when they connected to the applied potential in series and in parallel.
"You have two identical capacitors and an external potential source.
For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of
Transferring charge and energy between capacitors
Submit
Previous Answers
Correct
IDENTIFY: Use the rules for series and for parallel capacitors to express the voltage for each capacitor in terms of the applied voltage. Express $U$, $Q$, and $E$ in terms of the capacitor voltage.
SET UP: Let the applied voltage be $V$. Let each capacitor have capacitance $C$. $U = \frac{1}{2}CV^2$ for a single capacitor with voltage $V$.
EXECUTE: Series: The voltage across each capacitor is $V/2$. The total energy stored is
$U_s = 2(\frac{1}{2}C(V/2)^2) = \frac{1}{4}CV^2$
Parallel: The voltage across each capacitor is $V$. The total energy stored is
$U_p = 2(\frac{1}{2}CV^2) = CV^2 \rightarrow U_p = 4U_s$
Part B
Compare the maximum amount of charge stored in the capacitor system in each case.
Submit Previous Answers Request Answer
Incorrect; Try Again; 4 attempts remaining

xercise 24.27 - Enhanced - with Solution
Compare the total energy stored in the capacitor system when they connected to the applied potential in series and in parallel.
"You have two identical capacitors and an external potential source.
For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of
Transferring charge and energy between capacitors
Submit
Previous Answers
Correct
IDENTIFY: Use the rules for series and for parallel capacitors to express the voltage for each capacitor in terms of the applied voltage. Express U, Q, and E in terms of the capacitor voltage.
SET UP: Let the applied voltage be V. Let each capacitor have capacitance C. U = (1)/(2)CV^2 for a single capacitor with voltage V.
EXECUTE: Series: The voltage across each capacitor is V/2. The total energy stored is
Us = 2((1)/(2)C(V/2)^2) = (1)/(4)CV^2
Parallel: The voltage across each capacitor is V. The total energy stored is
Up = 2((1)/(2)CV^2) = CV^2 → Up = 4Us
Part B
Compare the maximum amount of charge stored in the capacitor system in each case.
Submit Previous Answers Request Answer
Incorrect; Try Again; 4 attempts remaining

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