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Expand the logarithm as much as possible. Rewrite the expression as a sum, difference, or product of logs. \ln\left(\frac{1}{121k}\right)

          Expand the logarithm as much as possible. Rewrite the expression as a sum, difference, or product of logs.
\ln\left(\frac{1}{121k}\right)
        
Expand the logarithm as much as possible. Rewrite the expression as a sum, difference, or product of logs.
ln((1)/(121k))

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Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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Expand the logarithm as much as possible. Rewrite the expression as a sum, difference, or product of logs. ln((1)/(121^(k))) Expand the logarithm as much as possible. Rewrite the expression as a sum, difference, or product of logs. ln(1) - ln(121^k) Expand the logarithm as much as possible. Rewrite the expression as a sum, difference, or product of logs. 0 - k * ln(121) Expand the logarithm as much as possible. Rewrite the expression as a sum, difference, or product of logs. -k * ln(121) Expand the logarithm as much as possible. Rewrite the expression as a sum, difference, or product of logs. -ln(121) * k Expand the logarithm as much as possible. Rewrite the expression as a sum, difference, or product of logs. -kln(121) Expand the logarithm as much as possible. Rewrite the expression as a sum, difference, or product of logs. - kln(121)
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Transcript

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00:01 Student welcome to the solution generally the logarithm of a over b is equal to log a minus log b here we have the logarithm of 1 over 121 k so this would be equal to log 1 minus log 1 121 k so here we have one more identity log a b is equal to log a plus log b so we can use that also so this would be equal to log 1 minus log 121 plus log k which marks as the final answer this identity and this identity has helped us to reach at the final answer...
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