Homework-1: Problem 10 (1 point) 3x^2 + 3y^2 - 30x - 18y + 54 = 0 is the equation of a circle with center (h, k) and radius r for: h = and k = and r = Note: You can earn partial credit on this problem.
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To do this, we need to add and subtract \((10/2)^2 = 25\) inside the parentheses: \(x^2 - 10x + 25 + y^2 - 6y + 18 = 25\) Simplify the equation: \((x - 5)^2 + y^2 - 6y + 43 = 25\) Show more…
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