Question

Find all Solutions of $12\sin^2x - 4\cos x - 11 = 0$ in the interval $[0, 2\pi)$ Find all the solutions of $2 - \cos^2 x = 4\sin\frac{x}{2}$ in the interval $[0, 2\pi)$

          Find all Solutions of $12\sin^2x - 4\cos x - 11 = 0$ in the interval $[0, 2\pi)$ 
Find all the solutions of $2 - \cos^2 x = 4\sin\frac{x}{2}$ in the interval $[0, 2\pi)$

Find all Solutions of 12sin^2x - 4cos x - 11 = 0 in the interval [0, 2π)
Find all the solutions of 2 - cos^2 x = 4sin(x)/(2) in the interval [0, 2π)

Added by Shelly W.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Harmender Singh Yadav

05/22/2021

Step 1

Step 1: Use the identity $cos^2x=1-sin^2x$ to rewrite the equation as $2-(1-sin^2x)=4sin^2\frac{x}{2}$ Show more…

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Find all Solutions of $12sin^2x-4cosx-11=0$ in the interval $[0,2\pi)$ Find all the solutions of $2-cos^2x=4sin^2\frac{x}{2}$ in the interval $[0,2\pi)$