Question

Find all the real zeros of the polynomial. Use the quadratic formula if necessary. P(x) = 5x\textsuperscript{4} + 76x\textsuperscript{3} + 15x\textsuperscript{2} - 540x - 108 \begin{itemize} \item x = -3, x = -\frac{1}{5}, x = -6 \pm 6\sqrt{2} \item x = -3, x = -\frac{1}{5}, x = 6 \pm 6\sqrt{2} \item x = 3, x = -\frac{1}{5}, x = -6 \pm 6\sqrt{2} \item x = 3, x = \frac{1}{5}, x = -6 - 6\sqrt{2} \end{itemize}

          Find all the real zeros of the polynomial. Use the quadratic formula if necessary.
P(x) = 5x\textsuperscript{4} + 76x\textsuperscript{3} + 15x\textsuperscript{2} - 540x - 108
\begin{itemize}
    \item x = -3, x = -\frac{1}{5}, x = -6 \pm 6\sqrt{2}
    \item x = -3, x = -\frac{1}{5}, x = 6 \pm 6\sqrt{2}
    \item x = 3, x = -\frac{1}{5}, x = -6 \pm 6\sqrt{2}
    \item x = 3, x = \frac{1}{5}, x = -6 - 6\sqrt{2}
\end{itemize}

Find all the real zeros of the polynomial. Use the quadratic formula if necessary.
P(x) = 5x4 + 76x3 + 15x2 - 540x - 108

* x = -3, x = -(1)/(5), x = -6 ±6√(2)

* x = -3, x = -(1)/(5), x = 6 ±6√(2)

* x = 3, x = -(1)/(5), x = -6 ±6√(2)

* x = 3, x = (1)/(5), x = -6 - 6√(2)

Added by Mohamed M.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Anurag Kumar

Step 1

We can start by factoring out the greatest common divisor of the coefficients, which is 1 in this case. So, the polynomial remains the same. Show more…

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Find all the real zeros of the polynomial. Use the quadratic formula if necessary: P(x) = 5x^2 + 76x + 15x^2 + 540 = 108 0 x = -3, x = -1/6 + 6âˆš2 x = -3, x = 5/6 - 6âˆš2 0 x = -1, x = 6 + 6âˆš2 x = -1, x = -6 - 6âˆš1