00:01
In this problem, we are given that there is a standard normal random variable z.
00:07
And for this normal distribution, the main value is zero and the standard deviation is one.
00:13
And we have to get the probabilities in the given cases.
00:16
So first, we have to compute the probability that the z score is less than 2 .67.
00:22
So using the z table, we get this as 0 .9962.
00:26
And in the next part, we have to determine the probability that the z score is less than 2 .67.
00:31
The z score is more than 0 .94.
00:34
So this can be written as 1 minus probability that the z score is less than 0 .94.
00:41
And using the z table, we find the probability that the z score is less than 0 .94 as 0 .8264.
00:50
And subtracting this from 1, we get 0 .1736 as the result...