Find the area of the parallelogram whose vertices are listed. (-3,0), (0,9), (6, -2), (9,7) The area of the parallelogram is square units.
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We can find the area of the parallelogram using the determinant method. Let $\vec{AB} = B - A = (0 - (-3), 9 - 0) = (3, 9)$ Let $\vec{AD} = D - A = (9 - (-3), 7 - 0) = (12, 7)$ The area of the parallelogram is given by the absolute value of the determinant of the Show more…
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