00:01
So to solve for this, we will use the arithmetic sequence formula.
00:06
So let me write the formula to be used.
00:13
A .n or the n term of the sequence equivalent to a1, the initial, i mean the first term, plus n, and the number of terms minus 1, multiplied by the common difference in the sequence.
00:29
So first let us find our a1.
00:34
So from the given our a1 is the first term which is negative 6.
00:40
And our n is equivalent to 6.
00:54
And then our d, the common difference is let's try a2 minus a1.
01:04
So that would mean negative 1 minus negative 6 the d is 5 and if we are to try and check the third term minus the second we have 4 minus negative 1 our t still 5 so we are correct the difference in the sequence is equivalent to 5 so using the above formula or the given formula for finding an n term in a sequence, let's just substitute our given.
01:47
So a .n are the sixth term...