Find the equation of the circle that passes through the points (2, -2), (3, 5), (-4, 6) using the given formula. Formula: (x - h)^2 + (y - k)^2 = r^2
Added by Alejandro G.
Step 1
Let's choose the points (2, -2) and (3, 5) to find the center. Midpoint of (2, -2) and (3, 5): ((2+3)/2, (-2+5)/2) = (2.5, 1.5) Slope of the line passing through (2, -2) and (3, 5): (5-(-2))/(3-2) = 7 Slope of the perpendicular bisector: -1/7 Equation of the Show more…
Show all steps
Close
Your feedback will help us improve your experience
Lauren Bernstein and 50 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find an equation, in the form $(x-h)^{2}+(y-k)^{2}=r^{2}$ of the circle passing through the given points. $$(0,8),(5,3), \text { and }(4,6)$$
Conic Sections and Quadratic Systems
The Circle and the Parabola
Find an equation of the circle of the form $x^{2}+y^{2}+a x+b y+c=0$ that passes through the given points. $$P(-5,5), \quad Q(-2,-4), \quad R(2,4)$$
Systems of Equations and Inequatities
Systems of Linear Equations in More Than Two Variables
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD