Find the first 4 terms of the recursively defined sequence. $a_1 = 4$, $a_2 = 3$, $a_{n+1} = a_n + a_{n-1}$ a3 = a4 =
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However, we can simplify the expressions for the second, third, and fourth terms: a2 = 83 - a3a4 a3 = 86 - a3a4 - a4a5 a4 = 90 - a3a4 - a4a5 - a5a6 Using these simplified expressions, we can find the first four terms: a1 = 81 a2 = 83 - a3a4 Show more…
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