Question

Find the five-number summary for the following 10 values: 38, 37, 33, 31, 28, 24, 21, 33, 6, 35. Minimum = Q1 = Median = Q3 = Maximum = Considering the data value 6 and using the 1.5 IQR rule, we would A. classify the value 6 as an outlier because it is more that 1.5 IQRs below the median. B. not classify the value 6 as an outlier because it is not more that 1.5 IQRs below the first quartile. C. not classify the value 6 as an outlier because it is not more that 1.5 IQRs below the median. D. classify the value 6 as an outlier because it is more that 1.5 IQRs below the first quartile.

          Find the five-number summary for the following 10 values:
38, 37, 33, 31, 28, 24, 21, 33, 6, 35.
Minimum = 
Q1 = 
Median = 
Q3 = 
Maximum = 
Considering the data value 6 and using the 1.5 IQR rule, we would
A. classify the value 6 as an outlier because it is more that 1.5 IQRs below the median.
B. not classify the value 6 as an outlier because it is not more that 1.5 IQRs below the first quartile.
C. not classify the value 6 as an outlier because it is not more that 1.5 IQRs below the median.
D. classify the value 6 as an outlier because it is more that 1.5 IQRs below the first quartile.

Find the five-number summary for the following 10 values:
38, 37, 33, 31, 28, 24, 21, 33, 6, 35.
Minimum =
Q1 =
Median =
Q3 =
Maximum =
Considering the data value 6 and using the 1.5 IQR rule, we would
A. classify the value 6 as an outlier because it is more that 1.5 IQRs below the median.
B. not classify the value 6 as an outlier because it is not more that 1.5 IQRs below the first quartile.
C. not classify the value 6 as an outlier because it is not more that 1.5 IQRs below the median.
D. classify the value 6 as an outlier because it is more that 1.5 IQRs below the first quartile.

Added by Richard C.

Question

Please give Ace some feedback