Question

Find the inverse function of $f$ informally. $f(x) = \frac{1}{9}x$ $f^{-1}(x) = $ Verify that $f(f^{-1}(x)) = x$. $f(f^{-1}(x)) = f(\Box)$ $= \Box$ $= \frac{\Box}{9}$ $= x$ Verify that $f^{-1}(f(x)) = x$. $f^{-1}(f(x)) = f^{-1}(\Box)$ $= \Box(\frac{1}{9}x)$ $= x$

          Find the inverse function of $f$ informally.
$f(x) = \frac{1}{9}x$
$f^{-1}(x) = $
Verify that $f(f^{-1}(x)) = x$.
$f(f^{-1}(x)) = f(\Box)$
$= \Box$
$= \frac{\Box}{9}$
$= x$
Verify that $f^{-1}(f(x)) = x$.
$f^{-1}(f(x)) = f^{-1}(\Box)$
$= \Box(\frac{1}{9}x)$
$= x$

Find the inverse function of f informally.
f(x) = (1)/(9)x
f^-1(x) =
Verify that f(f^-1(x)) = x.
f(f^-1(x)) = f()
=
= ()/(9)
= x
Verify that f^-1(f(x)) = x.
f^-1(f(x)) = f^-1()
= ((1)/(9)x)
= x

Added by Sarah W.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Sujit Kumar

09/18/2020

Step 1

Step 1: To find the inverse function, we need to solve for $x$ in terms of $y$ in the equation $y = f(x)$. Show more…

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Find the inverse function of $f$ informally. $f(x) = \frac{1}{9}x$ $f^{-1}(x) = $ Verify that $f(f^{-1}(x)) = x$. $f(f^{-1}(x)) = f($ $ = $ $ = \frac{}{9}$ $ = x$ Verify that $f^{-1}(f(x)) = x$. $f^{-1}(f(x)) = f^{-1}($ $ = $ $ = x$