The magnitude of a vector $\vec{v} = v_x\hat{i} + v_y\hat{j}$ is given by the formula $|\vec{v}| = \sqrt{v_x^2 + v_y^2}$.
In this case, $v_x = 14$ and $v_y = -11$.
So, $|\vec{v}| = \sqrt{(14)^2 + (-11)^2}$.
$|\vec{v}| = \sqrt{196 + 121}$
$|\vec{v}| =
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