Find the polynomial of lowest degree having leading coefficient 1, real coefficients with a zero of 4 (multiplicity 2), and zero 2-2i. P(x) = (Simplify your answer.)
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Also, 4 is a zero with multiplicity 2. Therefore, the polynomial can be written as $$P(x) = (x-4)^2(x-(2-2i))(x-(2+2i))$$ Show more…
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