Find the solution set of each equation in the interval: 0 ≤ x < 2π . cos 2x – sinx = 0 a.{ 0, π} b. {π/6, 5π/6} c. {π/2, π/6, π/3} d. {π/6, 5π/6, 3π/2}
Added by Samuel W.
Step 1
Substituting this in, we get: 1 - 2sin^2x - sinx = 0 Rearranging, we get: 2sin^2x + sinx - 1 = 0 Now, we can factor this quadratic equation: (2sinx - 1)(sinx + 1) = 0 Show more…
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